1^2-1=(1+1)(x-1)

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Solution for 1^2-1=(1+1)(x-1) equation: 



1^2-1=(1+1)(x-1)

We move all terms to the left:

1^2-1-((1+1)(x-1))=0

We add all the numbers together, and all the variables

-(2(x-1))-1+1^2=0

We add all the numbers together, and all the variables

-(2(x-1))=0



We calculate terms in parentheses: -(2(x-1)), so:

2(x-1)

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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